Distinguish between bonding molecular orbital | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(N/A) Bonding Molecular Orbitals $(BMO)$Antibonding Molecular Orbitals $(ABMO)$It is abbreviated as $BMO$. Its wave function is expressed by $\psi_{MO

Vedclass · Accepted Answer

Vedclass · Answer

(N/A) Bonding Molecular Orbitals $(BMO)$Antibonding Molecular Orbitals $(ABMO)$It is abbreviated as $BMO$. Its wave function is expressed by $\psi_{MO} = \psi_{A} + \psi_{B}$.It is abbreviated as $ABMO$. Its wave function is expressed by $\psi_{MO}^{*} = \psi_{A} - \psi_{B}$.They are formed by the additive effect of atomic orbitals.They are formed by the subtractive effect of atomic orbitals.Formation involves constructive interference of electron waves,reinforcing each other.Formation involves destructive interference of electron waves,canceling each other.Electron density is concentrated between the nuclei,reducing internuclear repulsion.Electron density is concentrated away from the space between the nuclei.No nodal plane is present between the nuclei.$A$ nodal plane (where electron density is zero) exists between the nuclei.Electrons in $BMO$ stabilize the molecule.Electrons in $ABMO$ destabilize the molecule.$BMO$ possesses lower energy than the combining atomic orbitals.$ABMO$ possesses higher energy than the combining atomic orbitals.$BMO$ is stable. Examples: $\sigma, \pi$.$ABMO$ is unstable. Examples: $\sigma^{*}, \pi^{*}$.

List-$I$ (Molecule / ion)	List-$II$ (Bond order)
$1$. $NO$	$i$. $1.5$
$2$. $CO$	$ii$. $2.0$
$3$. $O_2^{-}$	$iii$. $2.5$
$4$. $O_2$	$iv$. $3.0$

Distinguish between bonding molecular orbitals and antibonding molecular orbitals.

Similar Questions

Paramagnetism is exhibited by molecules:

Which one of the following does not exhibit paramagnetism?

Match List-$I$ with List-$II$ and select the correct option:
List-$I$ (Molecule / ion) List-$II$ (Bond order)
$1$. $NO$ $i$. $1.5$
$2$. $CO$ $ii$. $2.0$
$3$. $O_2^{-}$ $iii$. $2.5$
$4$. $O_2$ $iv$. $3.0$

If $P$ to $T$ are second period $p-$block elements,then which of the following graphs shows the correct relation between the number of valence electrons in $P_2$ to $T_2$ (corresponding molecules) and their bond order?

Which amongst the following is an incorrect statement?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Bonding Molecular Orbitals $(BMO)$	Antibonding Molecular Orbitals $(ABMO)$
It is abbreviated as $BMO$. Its wave function is expressed by $\psi_{MO} = \psi_{A} + \psi_{B}$.	It is abbreviated as $ABMO$. Its wave function is expressed by $\psi_{MO}^{*} = \psi_{A} - \psi_{B}$.
They are formed by the additive effect of atomic orbitals.	They are formed by the subtractive effect of atomic orbitals.
Formation involves constructive interference of electron waves,reinforcing each other.	Formation involves destructive interference of electron waves,canceling each other.
Electron density is concentrated between the nuclei,reducing internuclear repulsion.	Electron density is concentrated away from the space between the nuclei.
No nodal plane is present between the nuclei.	$A$ nodal plane (where electron density is zero) exists between the nuclei.
Electrons in $BMO$ stabilize the molecule.	Electrons in $ABMO$ destabilize the molecule.
$BMO$ possesses lower energy than the combining atomic orbitals.	$ABMO$ possesses higher energy than the combining atomic orbitals.
$BMO$ is stable. Examples: $\sigma, \pi$.	$ABMO$ is unstable. Examples: $\sigma^{}, \pi^{}$.