Give the difference between an Ammeter and a Voltmeter.

In a moving coil galvanometer,the deflection of the coil $\theta$ is related to the electrical current $i$ by the relation

$A$ galvanometer has a resistance of $7\,\Omega$ and gives a full-scale deflection for a current of $1.0\,A$. How will you convert it into a voltmeter of range $10\,V$?

An ammeter has a range of $1 \ A$ without a shunt. The range of the ammeter can be changed by using different shunt resistances. What is the nature of the graph between the shunt resistance and the range?

To find the resistance of a galvanometer by the half-deflection method,the following circuit is used with resistances $R_1 = 9970\,\Omega$,$R_2 = 30\,\Omega$,and $R_3 = 0\,\Omega$. The deflection in the galvanometer is $d$. With $R_3 = 107\,\Omega$,the deflection changes to $\frac{d}{2}$. The galvanometer resistance is approximately ............... $\Omega$.

$A$ moving coil galvanometer has $100$ equal divisions. Its current sensitivity is $10$ divisions per milliampere and voltage sensitivity is $2$ divisions per millivolt. In order that each division reads $1 \ V$,the resistance in Ohm's needed to be connected in series with the coil will be