Provide evidence that $[Co(NH_3)_5Cl]SO_4$ and $[Co(NH_3)_5SO_4]Cl$ are ionization isomers.

(N/A) Ionization isomers produce different ions in solution.
$1$. When $[Co(NH_3)_5Cl]SO_4$ is treated with $BaCl_2$ solution,it gives a white precipitate of $BaSO_4$,confirming the presence of $SO_4^{2-}$ ions in the ionization sphere:
$[Co(NH_3)_5Cl]SO_4 + Ba^{2+} \to [Co(NH_3)_5Cl]^{2+} + BaSO_4 \downarrow (\text{white precipitate})$.
$2$. When $[Co(NH_3)_5SO_4]Cl$ is treated with $AgNO_3$ solution,it gives a white precipitate of $AgCl$,confirming the presence of $Cl^-$ ions in the ionization sphere:
$[Co(NH_3)_5SO_4]Cl + Ag^+ \to [Co(NH_3)_5SO_4]^+ + AgCl \downarrow (\text{white precipitate})$.
Since they yield different ions in aqueous solution,they are ionization isomers.