Draw the Lewis structure of $NO_2^-$.

(N/A) To draw the Lewis structure of the nitrite ion,$NO_2^-$,follow these steps:
$1$. Calculate the total number of valence electrons: $N$ $(5)$ + $2 \times O$ $(6 \times 2 = 12)$ + $1$ (negative charge) = $18$ valence electrons.
$2$. Place the nitrogen atom in the center and connect the two oxygen atoms with single bonds.
$3$. Distribute the remaining electrons to complete the octets of the oxygen atoms.
$4$. Since nitrogen does not have a complete octet,form a double bond with one of the oxygen atoms.
$5$. The resulting structure exhibits resonance,where the double bond alternates between the two oxygen atoms.
The correct Lewis resonance structures are:
$[O=N-O]^- \leftrightarrow [O-N=O]^-$