Class 12Chemistry8-2.Carboxylic acids and Their derivativeMix Examples-Carboxylic acids and Their derivative
MediumProvide the name,common formula,simple structure,and examples of homologous series containing the carbonyl group.
(N/A) The homologous series containing the carbonyl group $(C=O)$ are summarized in the table below:
| Group (Series) | Common formula | Simple structure | Example |
|---|---|---|---|
| $(i)$ Aldehyde | $RCHO$ | $R-C(=O)-H$ | $CH_3-C(=O)-H$ |
| (ii) Ketone | $RCOR'$ | $R-C(=O)-R'$ | $CH_3-C(=O)-CH_3$ |
| (iii) Carboxylic acid | $RCOOH$ | $R-C(=O)-OH$ | $CH_3-C(=O)-OH$ |
| (iv) Acyl halide | $RCOX$ | $R-C(=O)-X$ | $CH_3-C(=O)-Cl$ |
| $(v)$ Amide | $RCONH_2$ | $R-C(=O)-NH_2$ | $CH_3-C(=O)-NH_2$ |
| (vi) Acid anhydride | $(RCO)_2O$ | $R-C(=O)-O-C(=O)-R$ | $CH_3-C(=O)-O-C(=O)-CH_3$ |
| (vii) Ester | $RCOOR'$ | $R-C(=O)-OR'$ | $CH_3-C(=O)-OC_2H_5$ |
Explore More
Similar Questions
Match the reactant in Column-$I$ with the reaction in Column-$II$:
Column-$I$ Column-$II$ $(i)$ Acetic acid $(a)$ Stephen $(ii)$ Sodium phenate $(b)$ Friedel-Crafts $(iii)$ Methyl cyanide $(c)$ $HVZ$ $(iv)$ Toluene $(d)$ Kolbe's
| Column-$I$ | Column-$II$ |
| $(i)$ Acetic acid | $(a)$ Stephen |
| $(ii)$ Sodium phenate | $(b)$ Friedel-Crafts |
| $(iii)$ Methyl cyanide | $(c)$ $HVZ$ |
| $(iv)$ Toluene | $(d)$ Kolbe's |
The major product of the following reaction sequence is
Which of the following reactions produce carboxylic acids?
$(a)$ $MnO_2$ with $CH_3COCH_3$
$(b)$ $Ph-CCl_3 \xrightarrow[(ii) H_2O/H^+]{(i) aq. NaOH} PhCOOH$
$(c)$ $C_2H_5Br \xrightarrow[(iii) H_2O/H^+]{(i) Mg, (ii) CO_2} C_2H_5COOH$
$(d)$ $CH_3CH=CHCH_3 \xrightarrow[\Delta]{K_2Cr_2O_7/H_2SO_4} 2CH_3COOH$
$(a)$ $MnO_2$ with $CH_3COCH_3$
$(b)$ $Ph-CCl_3 \xrightarrow[(ii) H_2O/H^+]{(i) aq. NaOH} PhCOOH$
$(c)$ $C_2H_5Br \xrightarrow[(iii) H_2O/H^+]{(i) Mg, (ii) CO_2} C_2H_5COOH$
$(d)$ $CH_3CH=CHCH_3 \xrightarrow[\Delta]{K_2Cr_2O_7/H_2SO_4} 2CH_3COOH$
The product $(X)$ of the reaction is:
Difficult
View SolutionAt which value of $n$ does the formation of a six-membered ring take place in the following reaction?
$Br-(CH_2)_n-CH_2-Br + CH_2(CO_2Et)_2 \xrightarrow{NaOEt, EtOH} \text{cyclic product}$
$Br-(CH_2)_n-CH_2-Br + CH_2(CO_2Et)_2 \xrightarrow{NaOEt, EtOH} \text{cyclic product}$
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo