Give the major product formed by heating CH_3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction of an ether with $HI$ proceeds via an $S_N1$ or $S_N2$ mechanism depending on the nature of the alkyl groups attached to the oxygen a

Vedclass · Accepted Answer

$CH_3-CH_2-CH_2-OH + CH_3-CH_2-C(CH_3)_2-I$

Vedclass · Answer

(D) The reaction of an ether with $HI$ proceeds via an $S_N1$ or $S_N2$ mechanism depending on the nature of the alkyl groups attached to the oxygen atom.In the given ether,$CH_3-CH_2-CH_2-O-C(CH_3)_2-CH_2-CH_3$,one alkyl group is a primary alkyl group ($n$-propyl) and the other is a tertiary alkyl group ($3$-methylpentan$-3-$yl group).When an ether has a tertiary alkyl group,the reaction follows the $S_N1$ mechanism because the tertiary carbocation is highly stable.The oxygen atom is protonated by $HI$ to form an oxonium ion,which then undergoes cleavage to form the most stable carbocation.The tertiary carbocation,$CH_3-CH_2-C^+(CH_3)_2$,is formed,which then reacts with the iodide ion $(I^-)$ to form the tertiary alkyl iodide,$CH_3-CH_2-C(I)(CH_3)_2$.The remaining part forms the primary alcohol,$CH_3-CH_2-CH_2-OH$.Therefore,the major products are $CH_3-CH_2-CH_2-OH$ and $CH_3-CH_2-C(I)(CH_3)_2$.

Give the major product formed by heating $CH_3-CH_2-CH_2-O-C(CH_3)_2-CH_2-CH_3$ with $HI$.

Similar Questions

The $IUPAC$ name of an unsymmetrical ether with the molecular formula $= C_4H_{10}O$ is:

The ether that undergoes electrophilic substitution reactions is

Which one of the following reactions does not yield an alkyl halide?

The product of the reaction is $?$

Ether on carbonylation gives:

Vedclass Test Series

Exam Paper Generator

Online Exam Module