Give the order of energy of orbitals in a multi-electron atom.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The energy order of orbitals in multi-electron atoms is determined by the $(n+l)$ rule,where $n$ is the principal quantum number and $l$ is the azimuthal quantum number. Orbitals with a lower $(n+l)$ value have lower energy. If two orbitals have the same $(n+l)$ value,the one with the lower $n$ value has lower energy.
The energy order of orbitals is:
$1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7p$
Factors affecting the energy of orbitals:
$(i)$ The attraction of the orbital towards the nucleus and repulsion between electrons.
$(ii)$ The shielding effect provided by inner shell electrons.
$(iii)$ The penetration effect of orbitals,which follows the order $s > p > d > f$ for a given shell.
$(iv)$ The effective nuclear charge $(Z_{eff})$ experienced by the electrons.

Explore More

Similar Questions

The orbital angular momentum for a $d$-electron is

Explain the energy order of orbitals in multielectron atoms.

Difficult
View Solution

Match List-$I$ with List-$II$ :
List-$I$ (Quantum numbers)List-$II$ (Orbital)
$A$. $n = 2, l = 1$$I$. $3d$
$B$. $n = 4, l = 0$$II$. $2p$
$C$. $n = 5, l = 3$$III$. $4s$
$D$. $n = 3, l = 2$$IV$. $5f$

Choose the correct answer from the options given below :

Which of the following sets of quantum numbers is not possible?

Which of the following statements concerning the four quantum numbers is false?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo