Given below are two statements:
Statement $I$: If the number of turns in the coil of a moving coil galvanometer is doubled,then the current sensitivity becomes double.
Statement $II$: Increasing the current sensitivity of a moving coil galvanometer by only increasing the number of turns in the coil will also increase its voltage sensitivity in the same ratio.
In the light of the above statements,choose the correct answer from the options given below:

  • A
    Statement $I$ is false but Statement $II$ is true.
  • B
    Both Statement $I$ and Statement $II$ are true.
  • C
    Both Statement $I$ and Statement $II$ are false.
  • D
    Statement $I$ is true but Statement $II$ is false.

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An ammeter with a resistance of $1\, \Omega$ can measure up to $10\, mA$. To convert it into a voltmeter that can measure up to $10\, V$,what resistance (in $\Omega$) must be connected in series?

To find the resistance of a galvanometer by the half-deflection method,the experimental data obtained are given in the table below:
$S. No.$Resistance $R \ (\Omega)$Deflection $(\theta)$Shunt $S \ (\Omega)$Half deflection $(\theta / 2)$Galvanometer resistance $(G)$
$1$$3300$$30$$80$$15$$G_1$
$2$$5000$$20$$80$$10$$G_2$

From the above data,the galvanometer resistance $G$ will be near to: (in $\Omega$)

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The percentage error in the reading of the voltmeter in the figure shown here is nearly ............ $\%$

$A$ galvanometer coil has a resistance of $50 \Omega$ and the meter shows full scale deflection for a current of $5 \text{ mA}$. This galvanometer is converted into a voltmeter of range $0-20 \text{ V}$ by connecting:

If $n$ represents the actual number of deflections in a converted galvanometer of resistance $G$ and shunt resistance $S$,then the total current $I$ when its figure of merit is $K$ will be:

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