Given below are two statements:Statement I: I | vedclass

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(A) Brewster's Law states that $	an 	heta_B = \frac{\mu_2}{\mu_1}$,where $\mu_1$ is the refractive index of the incident medium and $\mu_2$ is the r

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Statement $I$ is true but Statement $II$ is false.

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(A) Brewster's Law states that $	an 	heta_B = \frac{\mu_2}{\mu_1}$,where $\mu_1$ is the refractive index of the incident medium and $\mu_2$ is the refractive index of the refracting medium.For light propagating from air $(\mu_a = 1)$ to glass $(\mu_g = \mu)$,$	an 	heta_B = \frac{\mu}{1} = \mu$.For light propagating from glass $(\mu_g = \mu)$ to air $(\mu_a = 1)$,let the Brewster's angle be $	heta'_B$. Then $	an 	heta'_B = \frac{\mu_a}{\mu_g} = \frac{1}{\mu} = \cot 	heta_B = 	an(\frac{\pi}{2} - 	heta_B)$.Thus,$	heta'_B = \frac{\pi}{2} - 	heta_B$. Statement $I$ is true.For light propagating from glass to air,$	an 	heta'_B = \frac{1}{\mu_g}$. Statement $II$ claims it is $	an^{-1}(\mu_g)$,which is incorrect. Statement $II$ is false.

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