Given below are two statements: one is labell | vedclass

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(D) The binding energy per nucleon curve shows that for nuclei with mass numbers between $30$ and $170$, the binding energy per nucleon is nearly cons

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Both $A$ and $R$ are true and $R$ is the correct explanation of $A$.

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(D) The binding energy per nucleon curve shows that for nuclei with mass numbers between $30$ and $170$, the binding energy per nucleon is nearly constant (approximately $8 	ext{ MeV}$ per nucleon).This happens because the nuclear force is short-ranged, meaning a nucleon only interacts with its nearest neighbors.As the mass number increases, the number of neighbors remains effectively constant for a given nucleon, making the binding energy per nucleon independent of the total number of nucleons.Therefore, both the Assertion and the Reason are true, and the short-range nature of the nuclear force is the reason for the saturation of binding energy per nucleon.

Similar Questions

$M_p$ denotes the mass of a proton and $M_n$ that of a neutron. $A$ given nucleus,of binding energy $B$,contains $Z$ protons and $N$ neutrons. The mass $M(N, Z)$ of the nucleus is given by ($c$ is the velocity of light):

If $M_0$ is the mass of isotope ${ }_{5}^{12} B$,$M_p$ and $M_n$ are the masses of a proton and a neutron respectively,then the nuclear binding energy of the isotope is:

In the nuclear reaction $_1^2H + _1^3H \to _2^4He + _0^1n$, if the binding energies of $_1^2H$, $_1^3H$, and $_2^4He$ are respectively $a$, $b$, and $c$ (in $MeV$), then the energy (in $MeV$) released in this reaction is:

The mass of an $\alpha$-particle is

The energy equivalent to a mass of $1 \,kg$ is

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