Given below are two statements:Statement I: [ | vedclass

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(D) Statement $I$:$1.$ $[Mn(CN)_6]^{3-}: Mn^{3+} = [Ar] 3d^4$. $CN^{-}$ is a strong field ligand. Configuration: $t_{2g}^4 e_g^0$. Hybridization: $d^2

Vedclass · Accepted Answer

Both statement $I$ and statement $II$ are true

Vedclass · Answer

(D) Statement $I$:$1.$ $[Mn(CN)_6]^{3-}: Mn^{3+} = [Ar] 3d^4$. $CN^{-}$ is a strong field ligand. Configuration: $t_{2g}^4 e_g^0$. Hybridization: $d^2sp^3$.$2.$ $[Fe(CN)_6]^{3-}: Fe^{3+} = [Ar] 3d^5$. $CN^{-}$ is a strong field ligand. Configuration: $t_{2g}^5 e_g^0$. Hybridization: $d^2sp^3$.$3.$ $[Co(C_2O_4)_3]^{3-}: Co^{3+} = [Ar] 3d^6$. $C_2O_4^{2-}$ is a strong field ligand for $Co^{3+}$. Configuration: $t_{2g}^6 e_g^0$. Hybridization: $d^2sp^3$.Statement $I$ is correct.Statement $II$:$1.$ $[MnCl_6]^{3-}: Mn^{3+} = [Ar] 3d^4$. $Cl^{-}$ is a weak field ligand. Configuration: $t_{2g}^3 e_g^1$. Unpaired electrons = $4$. Paramagnetic.$2.$ $[FeF_6]^{3-}: Fe^{3+} = [Ar] 3d^5$. $F^{-}$ is a weak field ligand. Configuration: $t_{2g}^3 e_g^2$. Unpaired electrons = $5$. Paramagnetic.Statement $II$ is correct.

List-$I$ (Hybridisation)	List-$II$ (Compound/ion)
$A. sp^3d$	$I. [PtCl_4]^{2-}$
$B. sp^3d^2$	$II. SF_6$
$C. dsp^2$	$III. BCl_3$
$D. dsp^3$	$IV. PCl_5$
	$V. ClF_3$

Similar Questions

Among $[Ni(CO)_4]$,$[Ni(CN)_4]^{2-}$,and $[NiCl_4]^{2-}$ species,the hybridization states at the $Ni$ atom are,respectively:

Match the following:
List-$I$ (Hybridisation) List-$II$ (Compound/ion)
$A. sp^3d$ $I. [PtCl_4]^{2-}$
$B. sp^3d^2$ $II. SF_6$
$C. dsp^2$ $III. BCl_3$
$D. dsp^3$ $IV. PCl_5$
$V. ClF_3$

The correct match is:

Number of identical $Cr-O$ bonds in dichromate ion $Cr_2O_7^{2-}$ is

The number of unpaired electrons in $Ni(CO)_4$ is

The spin-only magnetic moment of $[MnBr_4]^{2-}$ is $5.9 \ BM$. Predict the geometry of the complex ion.

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