Given below are two statements:Statement-I: T | vedclass

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(D) The relationship between the linear momentum $p$ and the wavelength $\lambda$ of a photon is given by the de Broglie relation: $p = \frac{h}{\lamb

Vedclass · Accepted Answer

Statement $I$ is true but Statement $II$ is false.

Vedclass · Answer

(D) The relationship between the linear momentum $p$ and the wavelength $\lambda$ of a photon is given by the de Broglie relation: $p = \frac{h}{\lambda}$.Since $h$ (Planck's constant) is a constant,if two photons have equal linear momenta $(p_1 = p_2)$,they must have equal wavelengths $(\lambda_1 = \lambda_2)$. Thus,Statement-$I$ is true.The energy $E$ of a photon is given by $E = \frac{hc}{\lambda}$.From the relations $p = \frac{h}{\lambda}$ and $E = \frac{hc}{\lambda}$,it is clear that both momentum $p$ and energy $E$ are inversely proportional to the wavelength $\lambda$. Therefore,if the wavelength $\lambda$ is decreased,both the momentum $p$ and the energy $E$ of the photon will increase. Thus,Statement-$II$ is false.

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