Given the radius of Earth $R$ and the length of a day $T$,the height of a geostationary satellite is: [$G$ = Gravitational Constant,$M$ = Mass of Earth]

• A
  ${\left( {\frac{{4{\pi ^2}GM}}{{{T^2}}}} \right)^{1/3}}$
• B
  ${\left( {\frac{{4\pi GM}}{{{R^2}}}} \right)^{1/3}} - R$
• C
  ${\left( {\frac{{GM{T^2}}}{{4{\pi ^2}}}} \right)^{1/3}} - R$
• D
  ${\left( {\frac{{GM{T^2}}}{{4{\pi ^2}}}} \right)^{1/3}} + R$