Given that sqrt{20} = 4.472,find the square r | vedclass

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(C) First,convert the mixed fraction $2 \frac{2}{9}$ into an improper fraction: $2 \frac{2}{9} = \frac{2 	imes 9 + 2}{9} = \frac{18 + 2}{9} = \frac{2

Vedclass · Accepted Answer

$1.49$

Vedclass · Answer

(C) First,convert the mixed fraction $2 \frac{2}{9}$ into an improper fraction: $2 \frac{2}{9} = \frac{2 	imes 9 + 2}{9} = \frac{18 + 2}{9} = \frac{20}{9}$. Now,find the square root: $\sqrt{\frac{20}{9}} = \frac{\sqrt{20}}{\sqrt{9}}$. Given that $\sqrt{20} = 4.472$ and $\sqrt{9} = 3$,substitute these values: $\frac{4.472}{3} = 1.49066...$. Rounding to two decimal places,we get $1.49$.

Given that $\sqrt{20} = 4.472$,find the square root of $2 \frac{2}{9}$ up to two places of decimals.

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