Given that $\sqrt{4096} = 64$,the value of $\sqrt{4096} + \sqrt{40.96} + \sqrt{0.004096}$ is

  • A
    $70.4$
  • B
    $70.464$
  • C
    $71.104$
  • D
    $71.4$

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Similar Questions

$\sqrt{11449} \times \sqrt{6241} - (54)^{2} = \sqrt{?} + (74)^{2}$

What is the value of $\sqrt[3]{0.000064}$?

$\frac{\sqrt{24}+\sqrt{216}}{\sqrt{96}}=?$

$\sqrt{0.00004761} = ?$

$\frac{\sqrt{?}}{200} = 0.02$

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