Given that Lambda_{m}^{infty} = 133.4 , S , c | vedclass

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(B) According to Kohlrausch's law of independent migration of ions,the molar conductivity at infinite dilution for $AgCl$ can be calculated as:$\Lambd

Vedclass · Accepted Answer

$138$

Vedclass · Answer

(B) According to Kohlrausch's law of independent migration of ions,the molar conductivity at infinite dilution for $AgCl$ can be calculated as:$\Lambda_{m}^{\infty}(AgCl) = \Lambda_{m}^{\infty}(Ag^{+}) + \Lambda_{m}^{\infty}(Cl^{-})$Using the given values:$\Lambda_{m}^{\infty}(AgCl) = \Lambda_{m}^{\infty}(AgNO_{3}) + \Lambda_{m}^{\infty}(KCl) - \Lambda_{m}^{\infty}(KNO_{3})$Substituting the values:$= 133.4 + 149.9 - 144.9$$= 283.3 - 144.9$$= 138.4 \, S \, cm^{2} \, mol^{-1}$Rounding to the nearest integer,the value is $138 \, S \, cm^{2} \, mol^{-1}$.

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