Given three points $P, Q, R$ with $P(5, 3)$ and $R$ lies on the $x-$ axis. If the equation of $RQ$ is $x - 2y = 2$ and $PQ$ is parallel to the $x-$ axis,then the centroid of $\Delta PQR$ lies on the line

  • A
    $x - 2y + 1 = 0$
  • B
    $2x + y - 9 = 0$
  • C
    $2x - 5y = 0$
  • D
    $5x - 2y = 0$

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