Glucose gives a silver mirror with ammoniacal | vedclass

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Question

(A) Glucose gives a silver mirror test (Tollens' test) with ammoniacal silver nitrate due to the presence of the $-CHO$ (aldehyde) group in its open-c

Vedclass · Accepted Answer

aldehyde group

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(A) Glucose gives a silver mirror test (Tollens' test) with ammoniacal silver nitrate due to the presence of the $-CHO$ (aldehyde) group in its open-chain structure.$CH_2OH(CHOH)_4CHO + 2[Ag(NH_3)_2]^+ + 3OH^- \rightarrow CH_2OH(CHOH)_4COO^- + 2Ag(s) + 4NH_3 + 2H_2O$The formation of metallic silver $(Ag)$ results in the silver mirror.

Glucose gives a silver mirror with ammoniacal silver nitrate because it has:

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