Glucose gives many reactions of aldehyde,beca | vedclass

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Question

(D) Glucose exists in a cyclic hemiacetal form in the solid state,but in aqueous solution,it exists in equilibrium with its open-chain aldehyde form.

Vedclass · Accepted Answer

It is a hemiacetal in equilibrium with its aldehyde form in solution

Vedclass · Answer

(D) Glucose exists in a cyclic hemiacetal form in the solid state,but in aqueous solution,it exists in equilibrium with its open-chain aldehyde form. This open-chain form contains a free $-CHO$ group,which allows it to undergo characteristic reactions of aldehydes.

Glucose gives many reactions of aldehyde,because

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