(A) When glucose is heated with $HI$ and red phosphorus,it undergoes complete reduction to form $n$-hexane. The reaction is as follows:$CHO-(CHOH)_4-C

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) When glucose is heated with $HI$ and red phosphorus,it undergoes complete reduction to form $n$-hexane. The reaction is as follows:$CHO-(CHOH)_4-CH_2OH \xrightarrow{HI/\text{red } P} CH_3-(CH_2)_4-CH_3$ ($n$-hexane).This reaction confirms that glucose contains a straight chain of six carbon atoms.