(A) The gravitational potential difference $\Delta V$ for a height $h_1 = 20\,m$ is given as $2\,J/kg$.Since the gravitational field $g$ is uniform,th

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(A) The gravitational potential difference $\Delta V$ for a height $h_1 = 20\,m$ is given as $2\,J/kg$.Since the gravitational field $g$ is uniform,the potential difference is given by $\Delta V = g \cdot h$.Therefore,$g = \frac{\Delta V}{h_1} = \frac{2\,J/kg}{20\,m} = 0.1\,N/kg$ (or $m/s^2$).The work done $W$ in moving a body of mass $m = 5\,kg$ to a height $h_2 = 4\,m$ is given by $W = m \cdot g \cdot h_2$.Substituting the values: $W = 5\,kg \times 0.1\,N/kg \times 4\,m = 2\,J$.

Class 11 Physics Gravitation Gravitational Potential and Potential Energy of system

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Gravitational potential difference between the surface of a planet and a point situated at a height of $20\,m$ above its surface is $2\,J/kg$. If the gravitational field is uniform,then the work done in taking a $5\,kg$ body to a height of $4\,m$ above the surface will be ........ $J$.

A
$2$
B
$20$
C
$40$
D
$10$

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Gravitation

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Gravitational Potential and Potential Energy of system

$A$ particle of mass $10\, g$ is kept on the surface of a uniform sphere of mass $100\, kg$ and radius $10\, cm$. Find the work to be done against the gravitational force between them to take the particle far away from the sphere (you may take $G = 6.67 \times 10^{-11}\, Nm^2 / kg^2$).

MediumAIIMS 2008

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Taking the gravitational potential at a point at an infinite distance away as zero,the gravitational potential at a point $A$ is $-5 \, unit$. If the gravitational potential at a point at an infinite distance away is taken as $+10 \, units$,the potential at point $A$ is ......... $unit$.

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$A$ body of mass $m$ is taken from the Earth's surface to a height $h$ equal to twice the radius of the Earth $(R_e)$. The increase in potential energy will be: (where $g$ is the acceleration due to gravity on the surface of the Earth)

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Give the formula of gravitational potential at distance $r$ $(r > R_E)$ from the centre of the Earth.

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From a solid sphere of mass $M$ and radius $R$,a spherical portion of radius $R/2$ is removed,as shown in the figure. Taking gravitational potential $V = 0$ at $r = \infty$,the potential at the centre of the cavity thus formed is
($G =$ gravitational constant)

DifficultJEE MAIN 2015

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Gravitational potential difference between the surface of a planet and a point situated at a height of $20\,m$ above its surface is $2\,J/kg$. If the gravitational field is uniform,then the work done in taking a $5\,kg$ body to a height of $4\,m$ above the surface will be ........ $J$.

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$A$ particle of mass $10\, g$ is kept on the surface of a uniform sphere of mass $100\, kg$ and radius $10\, cm$. Find the work to be done against the gravitational force between them to take the particle far away from the sphere (you may take $G = 6.67 \times 10^{-11}\, Nm^2 / kg^2$).

Taking the gravitational potential at a point at an infinite distance away as zero,the gravitational potential at a point $A$ is $-5 \, unit$. If the gravitational potential at a point at an infinite distance away is taken as $+10 \, units$,the potential at point $A$ is ......... $unit$.

$A$ body of mass $m$ is taken from the Earth's surface to a height $h$ equal to twice the radius of the Earth $(R_e)$. The increase in potential energy will be: (where $g$ is the acceleration due to gravity on the surface of the Earth)

Give the formula of gravitational potential at distance $r$ $(r > R_E)$ from the centre of the Earth.

From a solid sphere of mass $M$ and radius $R$,a spherical portion of radius $R/2$ is removed,as shown in the figure. Taking gravitational potential $V = 0$ at $r = \infty$,the potential at the centre of the cavity thus formed is ($G =$ gravitational constant)

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From a solid sphere of mass $M$ and radius $R$,a spherical portion of radius $R/2$ is removed,as shown in the figure. Taking gravitational potential $V = 0$ at $r = \infty$,the potential at the centre of the cavity thus formed is
($G =$ gravitational constant)