Green compound (A) on decomposition gives gas | vedclass

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(A) The green compound $(A)$ is $FeSO_4 \cdot 7H_2O$. Upon heating, it decomposes to give $Fe_2O_3$ (red-brown residue), $SO_2$ (gas $(B)$), and $SO_3

Vedclass · Accepted Answer

$11$

Vedclass · Answer

(A) The green compound $(A)$ is $FeSO_4 \cdot 7H_2O$. Upon heating, it decomposes to give $Fe_2O_3$ (red-brown residue), $SO_2$ (gas $(B)$), and $SO_3$ (gas $(C)$).$SO_2$ reduces $KMnO_4$ (positive test).$(C) = SO_3$.$(C) + H_2SO_4 	o H_2S_2O_7$ (Oleum, $(D)$).$(D) + [O] 	o H_2S_2O_8$ (Peroxydisulphuric acid, $(E)$).Structure of $H_2S_2O_8$ (Marshall's acid): $HO-SO_2-O-O-SO_2-OH$.Counting $\sigma$ bonds in $H_2S_2O_8$: $2$ $(S-OH)$ bonds, $6$ $(S=O)$ bonds (each has $1 \sigma$), $1$ $(S-O-S)$ linkage ($2 \sigma$ bonds), and $1$ $(O-O)$ bond ($1 \sigma$ bond). Total $\sigma$ bonds = $2 + 6 + 2 + 1 = 11$.$(F) = H_2O_2$, $(G) = K_4[Fe(CN)_6]$, $(H) = CO$.

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