Haemolytic jaundice is caused due to a dominant gene but only $10\%$ of the people who carry the gene actually develop the disease. $A$ heterozygous man marries a homozygous normal woman; what proportion of the children would be expected to develop the haemolytic disease?

  • A
    $1/5$
  • B
    $1/10$
  • C
    $1/15$
  • D
    $1/20$

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