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(C) The mould is in the shape of a frustum of a cone.Given: Diameters of the circular faces are $d_1 = 35 \,cm$ and $d_2 = 30 \,cm$.Radii are $r_1 = \

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$14$

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(C) The mould is in the shape of a frustum of a cone.Given: Diameters of the circular faces are $d_1 = 35 \,cm$ and $d_2 = 30 \,cm$.Radii are $r_1 = \frac{35}{2} = 17.5 \,cm$ and $r_2 = \frac{30}{2} = 15 \,cm$.Vertical height $h = 14 \,cm$.The volume $V$ of a frustum of a cone is given by $V = \frac{1}{3} \pi h (r_1^2 + r_2^2 + r_1 r_2)$.$V = \frac{1}{3} 	imes \frac{22}{7} 	imes 14 	imes (17.5^2 + 15^2 + 17.5 	imes 15) \,cm^3$.$V = \frac{1}{3} 	imes 22 	imes 2 	imes (306.25 + 225 + 262.5) \,cm^3$.$V = \frac{44}{3} 	imes 793.75 \,cm^3 = 11641.66... \,cm^3 \approx 11641.67 \,cm^3$.Given that the mass of $1 \,cm^3$ of molasses is $1.2 \,g$.Total mass $= 11641.67 	imes 1.2 \,g = 13970.004 \,g$.Converting to $kg$: $13970.004 \div 1000 = 13.97 \,kg$.Rounding to the nearest whole number,the mass is approximately $14 \,kg$.

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