Heat is given to an ideal gas in an isotherma | vedclass

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(D) For an ideal gas,the internal energy $U$ is a function of temperature $T$ only,given by $dU = nC_{V}dT$.In an isothermal process,the temperature r

Vedclass · Accepted Answer

$C$ and $D$ only

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(D) For an ideal gas,the internal energy $U$ is a function of temperature $T$ only,given by $dU = nC_{V}dT$.In an isothermal process,the temperature remains constant,so $dT = 0$,which implies $dU = 0$. Thus,the internal energy of the gas does not change ($C$ is correct).According to the first law of thermodynamics,$dQ = dU + dW$.Since $dU = 0$,we have $dQ = dW$.Given that heat is supplied to the gas,$dQ > 0$. Therefore,$dW > 0$,which means the gas does positive work ($D$ is correct).Thus,the correct statements are $C$ and $D$.

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