The height of a geostationary satellite is ap | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) geostationary satellite orbits the Earth with a time period $T = 24 \, 	ext{hours} = 86400 \, 	ext{s}$.
Using the formula for the orbital radiu

Vedclass · Accepted Answer

$36000$

Vedclass · Answer

(D) geostationary satellite orbits the Earth with a time period $T = 24 \, 	ext{hours} = 86400 \, 	ext{s}$.
Using the formula for the orbital radius $r$ of a satellite: $r = \left( \frac{G M T^2}{4 \pi^2} ight)^{1/3}$.
Given $GM = g R^2$,where $g = 9.8 \, 	ext{m/s}^2$ and $R = 6.4 	imes 10^6 \, 	ext{m}$,the orbital radius $r$ is approximately $42200 \, 	ext{km}$.
The height $h$ above the Earth's surface is $h = r - R$.
$h = 42200 \, 	ext{km} - 6400 \, 	ext{km} = 35800 \, 	ext{km}$.
Rounding to the nearest standard value,the height is approximately $36000 \, 	ext{km}$.

The height of a geostationary satellite is approximately ........ $km$.

Similar Questions

$A$ satellite of mass $M$ is revolving in a circular orbit of radius $r$ around the Earth. The time period of revolution of the satellite is:

If an artificial satellite is moving in a circular orbit around the earth with a speed equal to half the magnitude of the escape velocity from the earth,the height of the satellite above the surface of the earth is

The mean radius of the earth is $R$,its angular speed on its own axis is $\omega$,and the acceleration due to gravity at the earth's surface is $g$. The cube of the radius of the orbit of a geostationary satellite will be

Write the equation and value of the orbital periodic time of a satellite revolving very close to the surface of the Earth.

If a satellite is orbiting the earth very close to its surface,then the orbital velocity mainly depends on

Vedclass Test Series

Exam Paper Generator

Online Exam Module