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(B) The average kinetic energy $(KE)$ of an ideal gas is given by the formula $KE = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant and $T$ i

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Same as that of a hydrogen molecule

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(B) The average kinetic energy $(KE)$ of an ideal gas is given by the formula $KE = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant and $T$ is the absolute temperature.Since the average kinetic energy depends only on the temperature $(T)$ and not on the mass of the gas particles,both helium $(He)$ and hydrogen $(H_2)$ will have the same average kinetic energy at the same temperature of $298 \ K$.Therefore,the correct option is $B$.

$A$ helium atom is two times heavier than a hydrogen molecule. At $298 \ K$,the average kinetic energy of helium is:

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