Heptane and octane form an ideal solution. At $373 \, K$,the vapour pressures of the two liquid components are $105.2 \, kPa$ and $46.8 \, kPa$ respectively. What will be the vapour pressure of a mixture of $26.0 \, g$ of heptane and $35 \, g$ of octane (in $, kPa$)?

$A$ solution that obeys Raoult's law is

For which of the following liquid mixtures $\Delta_{\text{mix}}H=0$ and $\Delta_{\text{mix}}V=0$?

Liquids $A$ and $B$ form an ideal solution over the entire range of composition. At temperature $T$,an equimolar binary solution of liquids $A$ and $B$ has a vapour pressure of $45 \ Torr$. At the same temperature,a new solution of $A$ and $B$ having mole fractions $x_A$ and $x_B$,respectively,has a vapour pressure of $22.5 \ Torr$. The value of $x_A / x_B$ in the new solution is . . . . . (Given that the vapour pressure of pure liquid $A$ is $20 \ Torr$ at temperature $T$)

$A$ solution of two liquids boils at a temperature higher than the boiling point of either of them. Hence,the binary solution shows:

Benzene and toluene form nearly ideal solutions. At $20\,^{\circ}C$,the vapour pressure of benzene is $75\,torr$ and that of toluene is $22\,torr$. The partial vapour pressure of benzene at $20\,^{\circ}C$ for a solution containing $78\,g$ of benzene and $46\,g$ of toluene in $torr$ is