Hexane xrightarrow[substack{773 K 10-20 at | vedclass

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Question

(D) The reaction sequence is as follows:$1$. Hexane $(C_6H_{14})$ undergoes aromatization in the presence of $Cr_2O_3$ at $773 \ K$ and $10-20 \ atm$

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$C_6H_5-COCH_3$

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(D) The reaction sequence is as follows:$1$. Hexane $(C_6H_{14})$ undergoes aromatization in the presence of $Cr_2O_3$ at $773 \ K$ and $10-20 \ atm$ pressure to form Benzene $(C_6H_6)$,which is $X$.$\underset{	ext{Hexane}}{C_6H_{14}}$ $\xrightarrow[\substack{773 \ K \ 10-20 \ atm}]{Cr_2O_3} \underset{	ext{Benzene}}{C_6H_6} (X)$$2$. Benzene $(X)$ then undergoes Friedel-Crafts acylation with acetyl chloride $(CH_3COCl)$ in the presence of anhydrous $AlCl_3$ to form Acetophenone $(C_6H_5COCH_3)$,which is $Y$.$\underset{	ext{Benzene}}{C_6H_6}$ $\xrightarrow[	ext{Anhydrous } AlCl_3]{CH_3COCl} \underset{	ext{Acetophenone}}{C_6H_5COCH_3} (Y)$This is an electrophilic substitution reaction.

Hexane $\xrightarrow[\substack{773 \ K \\ 10-20 \ atm}]{Cr_2O_3} X$ $\xrightarrow[\text{Anhydrous } AlCl_3]{CH_3COCl} Y$. $Y$ in the above sequence of reactions is

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