Highest fluoride and highest oxide of Mn are | vedclass

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Question

(A) The highest oxidation state of $Mn$ is $+7$. In fluorides,$Mn$ forms $MnF_4$ as its highest fluoride because the high electronegativity of fluorin

Vedclass · Accepted Answer

$MnF_4, Mn_2O_7$

Vedclass · Answer

(A) The highest oxidation state of $Mn$ is $+7$. In fluorides,$Mn$ forms $MnF_4$ as its highest fluoride because the high electronegativity of fluorine and the size of the $Mn$ atom limit the coordination number. In oxides,$Mn$ forms $Mn_2O_7$ (manganese heptoxide) where the oxidation state of $Mn$ is $+7$. Therefore,the highest fluoride is $MnF_4$ and the highest oxide is $Mn_2O_7$.

List-$I$	List-$II$
$A$. $Co^{2+}$	$I$. Yellow colour
$B$. $Fe^{2+}$	$II$. Dark green colour
$C$. $Ni^{2+}$	$III$. Blue colour
$D$. $Cu^{2+}$	$IV$. Pale green colour
	$V$. Pink colour

Highest fluoride and highest oxide of $Mn$ are respectively

Similar Questions

The presence of $Mn$ in steel produces

Match the following:
List-$I$ List-$II$
$A$. $Co^{2+}$ $I$. Yellow colour
$B$. $Fe^{2+}$ $II$. Dark green colour
$C$. $Ni^{2+}$ $III$. Blue colour
$D$. $Cu^{2+}$ $IV$. Pale green colour
$V$. Pink colour

The correct answer is

Complete the following reactions:
$(a)$ $4FeCr_2O_4 + 8Na_2CO_3 + 7O_2 \to 8Na_2CrO_4 + 2Fe_2O_3 + 8CO_2$
$(b)$ $2Na_2CrO_4 + 2H^+ \to Na_2Cr_2O_7 + 2Na^+ + H_2O$
Identify the species $X$ in both reactions.

Iron on reacting with carbon gives:

What is the composition of the alloy that exhibits the property of shape memory?

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