Highest oxidation state of manganese in fluor | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The ability of an element to exhibit a higher oxidation state depends on its ability to form multiple bonds with the central metal atom.Oxygen $(O

Vedclass · Accepted Answer

In covalent compounds fluorine can form single bond only while oxygen forms double bond

Vedclass · Answer

(D) The ability of an element to exhibit a higher oxidation state depends on its ability to form multiple bonds with the central metal atom.Oxygen $(O)$ is capable of forming $p\pi-d\pi$ multiple bonds with transition metals,which stabilizes higher oxidation states.In contrast,Fluorine $(F)$ can only form single covalent bonds $(F-M)$ and cannot form multiple bonds.Therefore,oxygen can stabilize the $ 7$ oxidation state of manganese in $Mn_2O_7$,whereas fluorine can only stabilize up to the $ 4$ oxidation state in $MnF_4$.

Highest oxidation state of manganese in fluoride is $+4$ $(MnF_4)$ but highest oxidation state in oxides is $+7$ $(Mn_2O_7)$ because $..........$

Similar Questions

Which of the following is the correct order of acidic character?

Discuss the chemical properties of lanthanoids.

Explain the trends in $E_{M^{3+}/M^{2+}}^{o}$ electrode potential.

$A$ transition metal exists in its highest oxidation state. It is expected to behave as

Which of these statements is not true?

Vedclass Test Series

Exam Paper Generator

Online Exam Module