How are $0.50 \, mol$ $Na_{2}CO_{3}$ and $0.50 \, M$ $Na_{2}CO_{3}$ different?
(N/A) $0.50 \, mol$ $Na_{2}CO_{3}$ represents a specific quantity of the substance in terms of moles. The mass of $0.50 \, mol$ $Na_{2}CO_{3}$ is calculated as: $0.50 \, mol \times 106 \, g \, mol^{-1} = 53 \, g$.
$0.50 \, M$ $Na_{2}CO_{3}$ represents the molarity of the solution,which means $0.50 \, mol$ of $Na_{2}CO_{3}$ is dissolved in $1 \, L$ of the solution.
Therefore,$0.50 \, mol$ refers to the amount of substance,while $0.50 \, M$ refers to the concentration of the solution.
$0.50 \, M$ $Na_{2}CO_{3}$ represents the molarity of the solution,which means $0.50 \, mol$ of $Na_{2}CO_{3}$ is dissolved in $1 \, L$ of the solution.
Therefore,$0.50 \, mol$ refers to the amount of substance,while $0.50 \, M$ refers to the concentration of the solution.
Explore More
Similar Questions
If $5 \ g$ $NaOH$ is dissolved in $450 \ mL$ of solution,the molarity of the solution is: $(Na=23, O=16, H=1 \ g \ mol^{-1})$ (in $M$)
Which unit of concentration value does not change with change in temperature?
The volume of water added to $500 \ mL$ of $0.5 \ M \ NaOH$ solution so that its strength becomes $10 \ mg \ mL^{-1}$ will be .......... $mL$.
Medium
View SolutionThe density of liquid $HCl$ is $1.17 \ g/cm^3$. What is its molarity?
Medium
View Solution$10.6 \, g$ of a substance of molecular weight $106$ was dissolved in $100 \, mL$. $10 \, mL$ of this solution was pipetted out into a $1000 \, mL$ flask and made up to the mark with distilled water. The molarity of the resulting solution is
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo