How is the gravitational force between two point masses affected when they are dipped in water,keeping the separation between them the same?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(C) The gravitational force between two point masses is given by Newton's law of gravitation: $F = \frac{G m_1 m_2}{r^2}$.
This formula shows that the gravitational force depends only on the masses $(m_1, m_2)$ and the distance $(r)$ between them.
It does not depend on the medium present between the masses.
Therefore,when the masses are dipped in water while keeping the separation constant,the gravitational force remains unchanged.

Explore More

Similar Questions

Mass $M$ is divided into two parts $xM$ and $(1-x)M$. For a given separation,the value of $x$ for which the gravitational attraction between the two pieces becomes maximum is

Consider an infinite distribution of point masses (each of mass $m$) placed on the $x$-axis as shown in the diagram. What is the gravitational force acting on the point mass placed at the origin?

Difficult
View Solution

The gravitational force between a hollow spherical shell (of radius $R$ and uniform density) and a point mass $m$ is $F$. Show the nature of the $F$ versus $r$ graph,where $r$ is the distance of the point mass from the centre of the hollow spherical shell.

If the mass of a body is $M$ on the Earth's surface,then the mass of the same body on the Moon's surface is:

Explain the vector form of Newton's universal law of gravitation.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo