How many Kg of tea,worth ₹ 25 per Kg,must be | vedclass

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(A) Given:$S.P.$ of the mixture $= ₹ 30$ per $Kg$Gain $= 10 \%$Calculation of Mean Cost Price $(C.P.)$:$C.P. = \frac{S.P. 	imes 100}{100 + 	ext{Gain

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$36$

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(A) Given:$S.P.$ of the mixture $= ₹ 30$ per $Kg$Gain $= 10 \%$Calculation of Mean Cost Price $(C.P.)$:$C.P. = \frac{S.P. 	imes 100}{100 + 	ext{Gain} \%}$$C.P. = \frac{30 	imes 100}{110} = ₹ \frac{300}{11}$ per $Kg$Using the Alligation method:Cost of cheaper tea $= ₹ 25$ per $Kg$Cost of superior tea $= ₹ 30$ per $Kg$Mean Price $= ₹ \frac{300}{11}$ per $Kg$Difference for cheaper tea $= 30 - \frac{300}{11} = \frac{330 - 300}{11} = \frac{30}{11}$Difference for superior tea $= \frac{300}{11} - 25 = \frac{300 - 275}{11} = \frac{25}{11}$Ratio of cheaper tea to superior tea $= \frac{30}{11} : \frac{25}{11} = 30 : 25 = 6 : 5$Let the quantity of cheaper tea be $x \ Kg$.Given,quantity of superior tea $= 30 \ Kg$.$\frac{x}{30} = \frac{6}{5}$$x = \frac{6}{5} 	imes 30 = 36 \ Kg$Thus,$36 \ Kg$ of cheaper tea must be blended.

How many $Kg$ of tea,worth ₹ $25$ per $Kg$,must be blended with $30 \ Kg$ of tea worth ₹ $30$ per $Kg$,so that by selling the blended variety at ₹ $30$ per $Kg$ there should be a gain of $10 \%$?

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