How many NAND gates are required to form an A | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To form an $AND$ gate using $NAND$ gates,we first pass the inputs $A$ and $B$ through a $NAND$ gate to get $\overline{A \cdot B}$.Then,we pass thi

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) To form an $AND$ gate using $NAND$ gates,we first pass the inputs $A$ and $B$ through a $NAND$ gate to get $\overline{A \cdot B}$.Then,we pass this output through another $NAND$ gate configured as a $NOT$ gate (by shorting its inputs together).Let the output of the first $NAND$ gate be $X = \overline{A \cdot B}$.The second $NAND$ gate acts as a $NOT$ gate,so its output $Y = \overline{X \cdot X} = \overline{X} = \overline{\overline{A \cdot B}} = A \cdot B$.Thus,two $NAND$ gates are required to form an $AND$ gate.

How many $NAND$ gates are required to form an $AND$ gate?

Similar Questions

The output $F$ of the logic circuit given below is

The output of the given combination of logic gates represents:

Identify the correct Logic Gate for the following output $(Y)$ of two inputs $A$ and $B$.

The correct output for the given logic circuit and inputs is:

The truth table for the following logic circuit is

Vedclass Test Series

Exam Paper Generator

Online Exam Module