(A) The structure of $P_4O_{10}$ consists of a central $P_4$ tetrahedron where each edge is bridged by an oxygen atom, forming $P-O-P$ linkages.There

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(A) The structure of $P_4O_{10}$ consists of a central $P_4$ tetrahedron where each edge is bridged by an oxygen atom, forming $P-O-P$ linkages.There are $6$ edges in a tetrahedron, and each edge is bridged by one oxygen atom.Therefore, there are $6$ $P-O-P$ linkages in the $P_4O_{10}$ molecule.