How many bond cleavages are required to conve | vedclass

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(D) Cubane is a polycyclic hydrocarbon with the formula $C_8H_8$,consisting of eight carbon atoms arranged in a cube.To convert a cyclic structure int

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$5$

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(D) Cubane is a polycyclic hydrocarbon with the formula $C_8H_8$,consisting of eight carbon atoms arranged in a cube.To convert a cyclic structure into a non-cyclic (acyclic) skeleton,we must break enough bonds to eliminate all rings.For a polycyclic system,the number of bonds to be broken is equal to the number of rings present.Cubane has $5$ faces (rings) that are fused together.As shown in the process: $1$. Breaking $2$ bonds opens the first set of rings.$2$. Breaking another $2$ bonds opens further rings.$3$. Breaking $1$ final bond results in a non-cyclic structure.Total bond cleavages required = $2 + 2 + 1 = 5$.

How many bond cleavages are required to convert cubane into a non-cyclic skeleton?

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