How many carbons are in the simplest alkyne h | vedclass

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(B) To have two side chains,the alkyne must have a quaternary carbon atom (a carbon bonded to four other carbons).In an alkyne,the triple bond involve

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$6$

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(B) To have two side chains,the alkyne must have a quaternary carbon atom (a carbon bonded to four other carbons).In an alkyne,the triple bond involves two carbons. To have two side chains,we need a structure like $3,3-$dimethylbut$-1-$yne.The structure is $HC \equiv C-C(CH_3)_2-CH_3$.Counting the carbons: $1$ (from $CH \equiv$),$1$ (from $C-$),$1$ (from the quaternary $C$),and $3$ (from the two methyl groups and the terminal methyl group).Total carbons = $1 + 1 + 1 + 3 = 6$.Thus,the simplest alkyne with two side chains has $6$ carbon atoms.

How many carbons are in the simplest alkyne having two side chains?

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