How many chiral compounds are possible on mon | vedclass

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(C) $2$-methylbutane is $CH_3-CH(CH_3)-CH_2-CH_3$. Monochlorination yields the following products: $1.$ $Cl-CH_2-CH(CH_3)-CH_2-CH_3$ ($1$-chloro-$2$-m

Vedclass · Accepted Answer

$4$

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(C) $2$-methylbutane is $CH_3-CH(CH_3)-CH_2-CH_3$. Monochlorination yields the following products: $1.$ $Cl-CH_2-CH(CH_3)-CH_2-CH_3$ ($1$-chloro-$2$-methylbutane): This molecule has a chiral center at $C_2$,so it exists as $2$ enantiomers. $2.$ $CH_3-CCl(CH_3)-CH_2-CH_3$ ($2$-chloro-$2$-methylbutane): This molecule is achiral. $3.$ $CH_3-CH(CH_3)-CHCl-CH_3$ ($2$-chloro-$3$-methylbutane): This molecule has a chiral center at $C_3$,so it exists as $2$ enantiomers. $4.$ $CH_3-CH(CH_3)-CH_2-CH_2Cl$ ($1$-chloro-$3$-methylbutane): This molecule is achiral. Total chiral compounds = $2 + 2 = 4$.

How many chiral compounds are possible on monochlorination of $2$-methylbutane?

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