How many cubes of 1 ,cm edge can be cut from | vedclass

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Question

(A) $1$. Volume of the cuboid = $length 	imes breadth 	imes height = 5 \,cm 	imes 4 \,cm 	imes 3 \,cm = 60 \,cm^3$. $2$. Volume of one cube = $(si

Vedclass · Accepted Answer

$60, 47:180$

Vedclass · Answer

(A) $1$. Volume of the cuboid = $length 	imes breadth 	imes height = 5 \,cm 	imes 4 \,cm 	imes 3 \,cm = 60 \,cm^3$. $2$. Volume of one cube = $(side)^3 = (1 \,cm)^3 = 1 \,cm^3$. $3$. Number of cubes = $\frac{	ext{Volume of cuboid}}{	ext{Volume of one cube}} = \frac{60 \,cm^3}{1 \,cm^3} = 60$. $4$. Total surface area of the cuboid = $2(lb + bh + lh) = 2(5 	imes 4 + 4 	imes 3 + 3 	imes 5) = 2(20 + 12 + 15) = 2(47) = 94 \,cm^2$. $5$. Total surface area of one cube = $6(side)^2 = 6(1)^2 = 6 \,cm^2$. $6$. Total surface area of $60$ cubes = $60 	imes 6 \,cm^2 = 360 \,cm^2$. $7$. Ratio = $\frac{94}{360} = \frac{47}{180}$ or $47:180$.

How many cubes of $1 \,cm$ edge can be cut from a wooden cuboid measuring $5 \,cm \times 4 \,cm \times 3 \,cm$? Find the ratio of the total surface area of the cuboid to the total surface area of all the cubes.

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