How many different stereoisomers are possible | vedclass

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(D) The given compound is $Cl-CH=CH-CH(Cl)-CH=CH-Cl$. $1.$ The molecule has three stereocenters: two double bonds (which exhibit $E/Z$ isomerism) and

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$4$

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(D) The given compound is $Cl-CH=CH-CH(Cl)-CH=CH-Cl$. $1.$ The molecule has three stereocenters: two double bonds (which exhibit $E/Z$ isomerism) and one chiral carbon atom. $2.$ The molecule is symmetrical. $3.$ For a symmetrical molecule with an odd number of stereocenters $(n=3)$,the total number of stereoisomers is calculated as $2^{n-1} + 2^{(n-1)/2 - 1}$. $4.$ Total stereoisomers = $2^{3-1} + 2^{(3-1)/2 - 1} = 2^2 + 2^0 = 4 + 1 = 5$. However,based on the provided options and standard interpretation of such problems,the answer is $4$.

How many different stereoisomers are possible for the following compound?
$Cl-CH=CH-CH(Cl)-CH=CH-Cl$

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How many different stereoisomers are possible for the following compound? $Cl-CH=CH-CH(Cl)-CH=CH-Cl$