How many electrons will there be in 1.6 C ch | vedclass

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(C) The quantization of electric charge is given by the formula $Q = ne$,where $Q$ is the total charge,$n$ is the number of electrons,and $e$ is the e

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$10^{19}$

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(C) The quantization of electric charge is given by the formula $Q = ne$,where $Q$ is the total charge,$n$ is the number of electrons,and $e$ is the elementary charge of an electron.Given: Total charge $Q = 1.6 \ C$ and the charge of one electron $e = 1.6 	imes 10^{-19} \ C$.Rearranging the formula to solve for $n$: $n = Q / e$.Substituting the values: $n = 1.6 \ C / (1.6 	imes 10^{-19} \ C) = 1 / 10^{-19} = 10^{19}$.Therefore,there are $10^{19}$ electrons in a charge of $1.6 \ C$.

How many electrons will there be in $1.6 \ C$ charge?

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