How many geometrical isomers are possible for | vedclass

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(B) The compound is $1,3,5$-trimethylcyclohexane. It has three chiral centers at positions $1, 3,$ and $5$. Due to the symmetry of the molecule,we can

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$2$

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(B) The compound is $1,3,5$-trimethylcyclohexane. It has three chiral centers at positions $1, 3,$ and $5$. Due to the symmetry of the molecule,we can have different spatial arrangements of the methyl groups relative to the ring plane. The possible geometrical isomers are: $1$. All three methyl groups are on the same side (cis,cis-isomer). $2$. Two methyl groups are on the same side and one is on the opposite side (cis,trans-isomer). These are the two possible geometrical isomers. Thus,the correct option is $B$.

How many geometrical isomers are possible for the compound $1,3,5$-trimethylcyclohexane?

Similar Questions

Draw $cis$ and $trans$ isomers of the following compounds. Also write their $IUPAC$ names:
$(i)$ $CHCl=CHCl$
$(ii)$ $C_{2}H_{5}C(CH_{3})=C(CH_{3})C_{2}H_{5}$

How many forms of benzaldoxime exist?

Which of the following does not show geometrical isomerism?

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