How many geometrical isomers are possible in the following coordination entities?
$(i)$ $[Cr(C_2O_4)_3]^{3-}$
$(ii)$ $[Co(NH_3)_3Cl_3]$
$(i)$ $[Cr(C_2O_4)_3]^{3-}$
$(ii)$ $[Co(NH_3)_3Cl_3]$
(N/A) $(i)$ For $[Cr(C_2O_4)_3]^{3-},$ no geometrical isomer is possible because the complex contains three identical symmetrical bidentate ligands,which results in a highly symmetric structure.
$(ii)$ For $[Co(NH_3)_3Cl_3],$ two geometrical isomers are possible: the facial $(fac)$ isomer,where the three identical ligands occupy the corners of one triangular face of the octahedron,and the meridional $(mer)$ isomer,where the three identical ligands occupy the positions around the meridian of the octahedron.
$(ii)$ For $[Co(NH_3)_3Cl_3],$ two geometrical isomers are possible: the facial $(fac)$ isomer,where the three identical ligands occupy the corners of one triangular face of the octahedron,and the meridional $(mer)$ isomer,where the three identical ligands occupy the positions around the meridian of the octahedron.
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Similar Questions
Identify the complex compound$(s)$ which is/are optically active and whose optical activity does not depend upon the orientation of the ligands around the metal cation:
$(i). [CoCl_3(NH_3)_3]$
$(ii). [Co(en)_3]Cl_3$
$(iii). [Co(C_2O_4)_2(NH_3)_2]^-$
$(iv). [CrCl_2(NH_3)_2(en)]^+$
$(i). [CoCl_3(NH_3)_3]$
$(ii). [Co(en)_3]Cl_3$
$(iii). [Co(C_2O_4)_2(NH_3)_2]^-$
$(iv). [CrCl_2(NH_3)_2(en)]^+$
Among the complex ions,$[Co(en)_2Cl_2]^{+}$,$[CrCl_2(C_2O_4)_2]^{3-}$,$[Fe(H_2O)_4(OH)_2]^{+}$,$[Fe(NH_3)_2(CN)_4]^{-}$,$[Co(en)_2(NH_3)Cl]^{2+}$ and $[Co(NH_3)_4(H_2O)Cl]^{2+}$,the number of complex ion$(s)$ that show$(s)$ cis-trans isomerism is
Which of the following complexes has a magnetic moment of $2.82 \ B.M.$?
Difficult
View SolutionThe complexes $[Co(NH_3)_6][Cr(CN)_6]$ and $[Cr(NH_3)_6][Co(CN)_6]$ are the examples of which type of isomerism?
MediumAIPMT 2011
View SolutionThe complex showing a spin-only magnetic moment of $2.82 \ B.M.$ is
MediumIIT 2010
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