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(D) Glycolysis is the process in which one molecule of glucose $(C_6H_{12}O_6)$ is broken down into two molecules of pyruvic acid $(CH_3COCOOH)$.There

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$26$

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(D) Glycolysis is the process in which one molecule of glucose $(C_6H_{12}O_6)$ is broken down into two molecules of pyruvic acid $(CH_3COCOOH)$.Therefore,the stoichiometry of the reaction is $1$ Glucose $\rightarrow$ $2$ Pyruvic acid.To calculate the number of glucose molecules required for $52$ pyruvic acid molecules,we divide the total number of pyruvic acid molecules by $2$.Number of glucose molecules = $\frac{52}{2} = 26$.Thus,$26$ glucose molecules are required to produce $52$ pyruvic acid molecules.

How many glucose molecules are required for the formation of $52$ pyruvic acid molecules at the end of glycolysis?

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