How many gram-equivalents of NaOH are require | vedclass

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(B) For acid-base neutralization,the number of gram-equivalents of acid must equal the number of gram-equivalents of base. The formula for gram-equiva

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$0.0025$

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(B) For acid-base neutralization,the number of gram-equivalents of acid must equal the number of gram-equivalents of base. The formula for gram-equivalents is: $	ext{Gram-equivalents} = 	ext{Normality} (N) 	imes 	ext{Volume} (V 	ext{ in } L)$. Given: Normality of $HCl$ $(N)$ = $0.1 \ N$ (decinormal). Volume of $HCl$ $(V)$ = $25 \ cm^{3} = 25 	imes 10^{-3} \ L = 0.025 \ L$. Therefore,gram-equivalents of $HCl = 0.1 	imes 0.025 = 0.0025$. Since the reaction is $HCl + NaOH ightarrow NaCl + H_2O$,the gram-equivalents of $NaOH$ required = gram-equivalents of $HCl = 0.0025$.

How many gram-equivalents of $NaOH$ are required to neutralize $25 \ cm^{3}$ of a decinormal $HCl$ solution?

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