How many grams of CH_3OH should be added to w | vedclass

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(A) The molarity $(M)$ is defined as the number of moles of solute per liter of solution.$M = \frac{	ext{moles of solute}}{	ext{volume of solution i

Vedclass · Accepted Answer

$9.6$

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(A) The molarity $(M)$ is defined as the number of moles of solute per liter of solution.$M = \frac{	ext{moles of solute}}{	ext{volume of solution in } L}$.Given: $M = 2 \ M$,Volume $(V)$ = $150 \ mL = 0.150 \ L$.Moles of $CH_3OH = M 	imes V = 2 \ mol/L 	imes 0.150 \ L = 0.3 \ mol$.Molar mass of $CH_3OH = (12 + 4 	imes 1 + 16) = 32 \ g/mol$.Mass of $CH_3OH = 	ext{moles} 	imes 	ext{molar mass} = 0.3 \ mol 	imes 32 \ g/mol = 9.6 \ g$.

How many grams of $CH_3OH$ should be added to water to prepare $150 \ mL$ solution of $2 \ M \ CH_3OH$?

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