How many minimum numbers of C-atom containing | vedclass

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Question

(B) For a molecule to show optical isomerism, it must be chiral, meaning it must possess at least one chiral center.$A$ chiral center is a carbon atom

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) For a molecule to show optical isomerism, it must be chiral, meaning it must possess at least one chiral center.$A$ chiral center is a carbon atom bonded to four different groups.In the case of a monohaloalkane with the general formula $C_nH_{2n+1}X$, we need to find the smallest alkane chain that can accommodate a chiral center.For $n=1$ (chloromethane) and $n=2$ (chloroethane), all carbons are bonded to at least two identical hydrogen atoms.For $n=3$ (chloropropane), $1$-chloropropane has no chiral center, and $2-$chloropropane has two identical methyl groups attached to the central carbon.For $n=4$, $2$-chlorobutane $(CH_3-CHCl-CH_2-CH_3)$ has a chiral center at the $C-2$ position because it is bonded to four different groups: $-H$, $-Cl$, $-CH_3$, and $-CH_2CH_3$.Therefore, the minimum number of carbon atoms required is $4$.

How many minimum numbers of $C$-atom containing monohaloalkane shows optical isomerism?

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