How many molecules of pyruvic acid are produc | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Glycolysis is the process in which one molecule of glucose $(C_6H_{12}O_6)$ is broken down into two molecules of pyruvic acid $(CH_3COCOOH)$.Given

Vedclass · Accepted Answer

$412$

Vedclass · Answer

(D) Glycolysis is the process in which one molecule of glucose $(C_6H_{12}O_6)$ is broken down into two molecules of pyruvic acid $(CH_3COCOOH)$.Given that $1$ molecule of glucose produces $2$ molecules of pyruvic acid.Therefore, $206$ molecules of glucose will produce $206 	imes 2 = 412$ molecules of pyruvic acid.Thus, the correct option is $D$.

How many molecules of pyruvic acid are produced at the end of glycolysis from $206$ molecules of glucose?

Similar Questions

The formation of $Acetyl-CoA$ from pyruvic acid is the result of its

Provide the flowchart of Glycolysis.

In glycolysis,the two $ATP$ molecules are consumed during . . . . . . .

The common step of both aerobic and anaerobic respiration is:

Name the phosphorylated ketotriose synthesized during respiration.

Vedclass Test Series

Exam Paper Generator

Online Exam Module