How many moles of $CO_2$ will be produced from $4 \ g$ carbon and $4 \ g$ oxygen in the following reaction?
$C + O_2 \rightarrow CO_2$

$50.0 \ kg$ of $N_{2(g)}$ and $10.0 \ kg$ of $H_{2(g)}$ are mixed to produce $NH_{3(g)}$. Calculate the amount of $NH_{3(g)}$ formed. Identify the limiting reagent in the production of $NH_{3(g)}$ in this situation.

$A$ closed $10 \, L$ vessel contains $1 \, L$ water gas $(1:1 \, CO : H_2)$ and $9 \, L$ air ($20 \% \, O_2$ by volume) at $STP$. The contents of the vessel are ignited. The number of moles of $CO_2$ in the vessel is closest to $.... \, mol$.

$5 \, \text{moles}$ of $A$,$6 \, \text{moles}$ of $B$,and an excess amount of $C$ are mixed to produce a final product $D$,according to the reactions:
$A + 2B \to I$
$I + C \to B + D$
What is the maximum number of moles of $D$ that can be produced,assuming that the products formed can be reused in the reactions?

If $5$ moles of $BaCl_2$ is mixed with $2$ moles of $Na_3PO_4$,the maximum number of moles of $Ba_3(PO_4)_2$ formed is $..........$ (Nearest integer)

$KMnO_4$ reacts with $KI$ in basic medium to form $I_2$ and $MnO_2$. When $250 \ mL$ of $0.1 \ M \ KI$ solution is mixed with $250 \ mL$ of $0.02 \ M \ KMnO_4$ in basic medium, what is the number of moles of $I_2$ formed?